Thread:HMcCoy/@comment-25501845-20151025131611/@comment-24808864-20151026021904

Balu.ur wrote: Hmm. I will try that way Thanks!

Here is what I have done So far : Cosecθ - Cotθ =   √2 Cotθ (Cosecθ - Cotθ)( Cosecθ  + Cotθ ) =   (√2 Cotθ) ( Cosecθ  + Cotθ ) Cosec^2θ - Cot^2 θ = (√2 Cotθ) ( Cosecθ + Cotθ ) {(a+b) (a-b) = a^2 - b^2} 1 = (√2 Cotθ) ( Cosecθ + Cotθ )                       ( Cosec^2θ - Cot^2 θ = 1) So, Cosecθ + Cot θ = 1/  (√2 Cotθ)

This is where I am Confused! Can   1/  (√2 Cotθ) be equal to  √2Cosec θ?

Iam Pretty Sure that its   √2Tan θ

SO, the Statement is False? Maybe I will try doing it in the way you suggested HM, I think that will succeed :1 You are making it too complicated. In mathematics when you are given some statement, you can use it. So just take the beginning statement and use it to solve for cos(x). After you do that you just substitute. and solve.