Thread:Balu.ur/@comment-25501845-20141011164049/@comment-25501845-20141012021839

Everyone, I got the answer from None other than Mr.HMcCoy.. Here you go !

I have to run to school very soon, so I won't have time to do hints and play back and forth. This also feels like a "fun" or "challenge" problem. That being said, **Spoiler Alert**

This problem has multiple solutions. For example, 41 mice and the cat eating 24 at a time.

41 mice to the first wall, cat eats 24, 17  mice left.

Next wall

17 mice double to 34, cat eats 24, 10 mice left.

Next wall

10 mice triple to 30, cat eats 24, 6 mice left.

Next wall

6 mice quadruple to 24, cat eats them all.

Any like-multiple of 41 and 24 should work (such as 82 and 48, or 123 and 72).

Algebraically, let x=the number of mice on the wall and y=the number of mice eaten by the cat and you will be trying to solve

This cat will be extremely obese. I am talking ten times Garfield here.