Thread:HMcCoy/@comment-25501845-20141011172252/@comment-24808864-20141011180213

This problem has multiple solutions. For example, 41 mice and the cat eating 24 at a time.

41 mice to the first wall, cat eats 24, 17  mice left.

Next wall

17 mice double to 34, cat eats 24, 10 mice left.

Next wall

10 mice triple to 30, cat eats 24, 6 mice left.

Next wall

6 mice quadruple to 24, cat eats them all.

Any like-multiple of 41 and 24 should work (such as 82 and 48, or 123 and 72).

Algebraically, let x=the number of mice on the wall and y=the number of mice eaten by the cat and you will be trying to solve

$$4(3(2(x-y)-y)-y)-y=0$$

This cat will be extremely obese. I am talking ten times Garfield here.