Thread:HMcCoy/@comment-25501845-20151025131611/@comment-28838092-20151025163213

Balu.ur wrote: I faced a tricky problem today, that is  If Cosecθ - Cotθ = √2 Cotθ Prove that Cosecθ + Cotθ =   √2 Cosecθ

I Did my best to answer it, but failed partially as I think. :/

Please Help :1

If Cosecθ - Cotθ =   √2 Cotθ

then 1/√2 (Cosecθ - Cotθ) = Cotθ

Cosecθ + Cotθ =   √2 Cosecθ

cosec(θ) + 1/√2 (Cosecθ - Cotθ) = √2 Cosecθ

cosec(θ) + 1/√2(Cosecθ) - 1/√2(Cotθ) = √2 Cosecθ

√2cosec(θ)/√2 + 1/√2(Cosecθ) - 1/√2(Cotθ) = ((√2)(√2)(Cosecθ))/√2

√2cosec(θ) + 1/(Cosecθ) - 1/(Cotθ) = ((√2)(√2)(Cosecθ))

√2cosec(θ) + cos(θ) - tan(θ) = 4 Cosecθ

cos(θ) - tan(θ) = (4-√2)(cosec(θ))

cos(θ) - sin(θ)/cos(θ) = (4-√2)(cosec(θ))

((cosθ)(cos(θ)))/cos(θ) - sin(θ)/cos(θ) = (4-√2)(1/cos(θ))

cos(θ)cos(θ) - sin(θ) = 4 - √2

Answer = :(

That's a tricky one :\