Thread:HMcCoy/@comment-25501845-20150620144553

Hello, HMcCoy, recently when I was answer some COmmunity Questions from KA, I saw a user asking what would be the Square Root of i(Imaginary Number). So, I tried to figure it out my own. I just wanted to know if its correct or not and understand the mistakes. Here is the proof :-

i = √-1 So, √i = √(√-1) right? Since i^1/2 = √i then, (√-1) ^1/2 = √i And, √-1 = (-1^1/2) SO,(√-1) ^1/2 = (-1^1/2) ^1/2 right? From (a^n)^m = a^nm Thus, (-1) ^1/4 = √i Which is the 4th root of -1.

This is just my Proof, I don know whether its correct or wrong if its wrong feel free to correct me.

Thanks, for taking time on this! And you are just 5 edits away from 10,000!  