Thread:HMcCoy/@comment-25501845-20160217140926/@comment-25501845-20160217154750

Anyhow, I found out the answer.

The equation was like this 3x/8 = 16+ √x

from which, I squared on both sides to get the equation  9x^2-832x+16384.

but, there is actually lot more easier way(which I cam up with right now). That is to assume √x to be y.

Forming another equation, 16+y = (3x^2)/8

3x^2 = 128 + 8y

0 = 3x^2 -8y - 128

Now, through Quadratic formula, y= -b±( √ b^2-4ac) / 2a

8± √ (64-4*3*-128) / 2*3 =>  8 ± √ (64+1536) / 6 =>  8 ± √ (1600) / 6

(8+40) / 6 taking positive = 48/6 = 8

<span style="font-size:small;font-weight:normal;color:rgb(84,84,84);font-family:arial,sans-serif;line-height:18.2px;">Since y=8= <span style="color:rgb(34,34,34);font-family:arial,sans-serif;font-size:16px;font-weight:normal;line-height:19.2px;">√x

x= 64

I appreciate your time spend and hope you will come up with a different way for answering such complex quadratics.