Thread:Balu.ur/@comment-25501845-20141110152352/@comment-25501845-20141111005323

HMcCoy wrote:

 1) Area of triangular surface is calculated as 1/2 * altitude (height) * base. If altitude of a triangle is increased by 5% and the base of the triangle is increased by 7%. What percenage would the area of the triangle increase?

a)3.33%

b)6.00%

c)12.00%

d)12.35%

Hint: Represent the unknown amounts by variables (perhaps h for height and b for base).
 * 1) Area of the triangle is $$ \frac{1}{2}(b\times h) $$.

.
 * 1) Increasing altitude by 5% would mean it would become $$1.05h$$ and increasing the base by 7% would mean it would become $$1.07b$$.
 * 2) Recalculate the area with these new values, and see how it compares to the original...this should give you an insight to the answer.

PS: You can also "pretend" that the base and altitude are convenient numbers (like one and one) and then use these convenient numbers to find the percentage increase. So, that would be 1/2 * b * h = 1/2 * 105b/100 * 107h/100 =

11235/10000 * 1/2 = 100 = 112.35. So increased percent will be 112.35 - 100 = 12.35!

Thank you...